Advertisements
Advertisements
Question
Multiply the following:
b3, 3b2, 7ab5
Solution
We have,
b3, 3b2 and 7ab5
∴ b3 × 3b2 × 7ab5 = (1 × 3 × 7)b3 × b2 × ab5
= 21ab10
APPEARS IN
RELATED QUESTIONS
Find the Product.
(5 − 2x) (3 + x)
Find the product.
(a2 + b) (a + b2)
Find the product of the following binomial: (2x + y)(2x + y)
Find the product of the following binomial: \[\left( \frac{4x}{5} - \frac{3y}{4} \right)\left( \frac{4x}{5} + \frac{3y}{4} \right)\]
Find the product of the following binomial: (2a3 + b3)(2a3 − b3)
Find the product of the following binomial: \[\left( x^4 + \frac{2}{x^2} \right)\left( x^4 - \frac{2}{x^2} \right)\]
Find the product of the following binomial: \[\left( x^3 + \frac{1}{x^3} \right)\left( x^3 - \frac{1}{x^3} \right)\]
Using the formula for squaring a binomial, evaluate the following: (102)2
Using the formula for squaring a binomial, evaluate the following: (99)2
Using the formula for squaring a binomial, evaluate the following: (999)2
