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Question
Obtain lens maker’s formula and mention its significance.
Solution
- Let us consider a thin lens made up of a medium of refractive index n2, is placed in a medium of refractive index n1. Let R1 and R2 be the radii of curvature of two spherical surfaces (1) and (2) respectively and P be the pole.
- The general equation for the refraction at a spherical surface is given from equation
`"n"_2/"v" - "n"_1/"u" = ("n"_2 - "n"_1)/"R"_1`
For the refracting surface (1) , the light goes from n1 to n2
- `"n"_2/"v" - "n"_1/"u" = ("n"_2 - "n"_1)/"R"_1`
For the refracting surface (2), the light goes from medium n2 to n1.
`"n"_1/"v" - "n"_2*"v'" = ("n"_1 - "n"_2)/"R"_2` - By adding
`"n"_1/"v" - "n"_1/"u" = ("n"_2 - "n"_1)(1/"R"_1 - 1/"R"_2)`
Further simplifying and rearranging,
`1/"v" - 1/"u" = (("n"_2 - "n"_1)/"n"_1)(1/"R"_1 - 1/"R"_2)`
`1/"v" - 1/"u" = ["n"_2/"n"_1 - 1] (1/"R"_1 - 1/"R"_2)` - If the object is at infinity, the image is formed at the focus of the lens.
Thus, for u = ∞, υ = f.
Then the equation becomes,
`1/"v" - 1/"u" = ["n"_2/"n"_1 - 1] (1/"R"_1 - 1/"R"_2)`
`1/"f" = ("n"_2/"n"_1 - 1) (1/"R"_1 - 1/"R"_2)` - If the refractive index of the lensis n2 and it is placed in air, then n2 = n and n1 = 1. So the equation becomes,
`1/"f" = ("n - 1")(1/"R"_1 - 1/"R"_2)`
The above equation is called the lens maker’s formula,
- `1/"v" - 1/"u" = 1/"f"`
This is called lens equation.
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