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Question
PQ is straight line of 13 units. If P has coordinate (2, 5) and Q has coordinate (x, – 7) find the possible values of x.
Solution
Here PQ = 13
PQ2 = 132
∴ (x - 2)2 + (-7 - 5)2 = 169
⇒ (x - 2)2 = 169 - 144
= 25 = 52
or
(x - 2) = ± 5
⇒ x = 7 or -3.
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