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Question
Show that the points A(- 2, 5), B(2, – 3) and C(0, 1) are collinear.
Solution
m1 = Slope ofAB
= `(-3 - 5)/(2 - (-2)) = (8)/(4)` = -2
m2 = slop of BC
= `(1 - (-3))/(0 - 2) = (4)/(-2)` = -2
Hence m1 = m2 = -2
So, AB is parallel to BC.
But B is common to AB and BC.
Hence, A, B and C must lies on the same line.
Hence proved.
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