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Simplify the Following: ( a 1 3 + a − 1 3 ) ( a 2 3 − 1 + a − 2 3 ) - Mathematics

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Question

Simplify the following:

`("a"^(1/3) + "a"^(-1/3))("a"^(2/3) - 1 + "a"^(-2/3))`

Sum

Solution

`("a"^(1/3) + "a"^(-1/3))("a"^(2/3) - 1 + "a"^(-2/3))`

= `"a"^(1/3)("a"^(2/3) -1 + "a"^(-2/3)) + "a"^(-1/3)("a"^(2/3) - 1 + "a"^(-2/3))`

= `("a"^(1/3) xx "a"^(2/3) - "a"^(1/3) xx 1 + "a"^(1/3) xx "a"^(-2/3)) + ("a"^(-1/3) xx "a"^(2/3) - "a"^(-1/3) xx 1 + "a"^(-1/3) xx "a"^(-2/3))`

= `("a"^(1/3 + 2/3) - "a"^(1/3) xx 1 + "a"^(1/3 + 2/3)) + ("a"^(-1/3 + 2/3) - "a"^(-1/3) + "a"^(-1/3 - 2/3))`   .....(Using am x an = am+n)

= `("a"^1 - "a"^(1/3) + "a"^(-1/3)) + ("a"^(1/3) - "a"^(-1/3) + "a"^-1)`

= `"a" - "a"^(1/3) + "a"^(-1/3) + "a"^(1/3) - "a"^(-1/3) + (1)/"a"`

= `"a"  + (1)/"a"`.

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Simplification of Expressions
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Chapter 9: Indices - Exercise 9.1

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 9 Indices
Exercise 9.1 | Q 7.05
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