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Question
Solve the previous problem if the paperweight is inverted at its place so that the spherical surface touches the paper.
Solution
Given,
Taking the radius of the paperweight as its thickness = 3 cm
Refractive index of the paperweight (μg) = 3/2
Refractive index of the air (μ1) = 1
Image shift is given by:
\[∆ t = \left( 1 - \frac{1}{\mu} \right)t\]
\[ = \left( 1 - \frac{2}{3} \right)3\]
\[ = \left( \frac{1}{3} \right)3\]
\[ = 1 \text{ cm }\]
The upper surface of the paperweight is flat and the spherical spherical surface is in contact with the printed letter.
Therefore, we will take it as a simple refraction problem.
Hence, the image will appear 1 cm above point A.
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