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Question
Solve problem:
The natural isotopic abundance of 10B is 19.60% and 11B is 80.40 %. The exact isotopic masses are 10.13 and 11.009 respectively. Calculate the average atomic mass of boron
Solution
Average atomic mass of Boron (B)
`=(("At. mass of" ""^10"B"xx%"Abundance")+("At. mass of" ""^11"B"xx%"Abundance"))/100`
= `((10.13 "u"xx19.60)+(11.009 "u"xx80.40))/100`
= 10.84 u
Average atomic mass of boron = 10.84 u
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