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Question
Solve the system of equations by using the method of cross multiplication:
2x + 5y – 1 = 0, 2x + 3y – 3 = 0
Solution
The given equations may be written as:
2x + 5y – 1 = 0 …….(i)
2x + 3y – 3 = 0 …….(ii)
Here a1 = 2, b1 = 5, c1 = -1, a2 = 2, b2 = 3 and c2 = -3
By cross multiplication, we have:
`∴ x/([5×(−3) −3 ×(−1)] )= y/([(−1) × 2 −(−3) × 2]) = 1/([2 × 3−2 × 5])`
`⇒x/((−15+3))= y/((−2+6) )= 1/((6−10))`
`⇒x/(−12) = y/4 = 1/(−4)`
`⇒x = (−12)/(−4 )= 3, y = 4/(−4 )= -1`
Hence, x = 3 and y = -1 is the required solution.
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