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Question
Solve the following problem.
What is the specific heat of metal if 50 cal of heat is needed to raise 6 kg of the metal from 20°C to 62 °C?
Solution
Given: Q = 50 cal, m = 6 kg, ΔT = 62 - 20 = 42 °C.
To find: Specific heat (s)
Formula: Q = ms ΔT
Calculation: From formula,
s = `"Q"/("m" Delta"T") = 50/(6 xx 42) = 0.198` cal/kg °C
Specific heat of metal is copper 0.198 cal/kg °C.
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