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Question
State an expression for K. E. (kinetic energy) and P. E. (potential energy) at displacement ‘x’ for a particle performing linear S.H. M. Represent them graphically. Find the displacement at which K. E. is equal to P. E.
Solution
`:.K.E.=1/2mw^2(A^2-X^2)`
`P.E.=1/2mw^2X^2`
K.E. = P.E.
`1/2K(A^2-X^2)=1/2KX^2`
∴ A2=2X2
`:.X^2=A^2/2`
`:.X=A/sqrt2`
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