English

State True or False for the following statement. If P = {1, 2}, then P × P × P = {(1, 1, 1), (2, 2, 2), (1, 2, 2), (2, 1, 1)} - Mathematics

Advertisements
Advertisements

Question

State True or False for the following statement.

If P = {1, 2}, then P × P × P = {(1, 1, 1), (2, 2, 2), (1, 2, 2), (2, 1, 1)}

Options

  • True

  • False

MCQ
True or False

Solution

This statement is False.

Explanation:

Given that P = {1, 2}

∴ P × P = {1, 2} × {1, 2} = {(1, 1), (1, 2), (2, 1), (2, 2)}

P × P × P = {(1, 1), (1, 2), (2, 1), (2, 2)} × {1, 2}

= {(1, 1, 1), (1, 1, 2), (1, 2, 1), (1, 2, 2), (2, 1, 1), (2, 1, 2), (2, 2, 1), (2, 2, 2)}

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Relations and Functions - Exercise [Page 33]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 11
Chapter 2 Relations and Functions
Exercise | Q 39 | Page 33

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

If the set A has 3 elements and the set B = {3, 4, 5}, then find the number of elements in (A × B).


If G = {7, 8} and H = {5, 4, 2}, find G × H and H × G.


If A × B = {(a, x), (a, y), (b, x), (b, y)}. Find A and B.


Let A = {1, 2} and B = {3, 4}. Write A × B. How many subsets will A × B have? List them.


The Cartesian product A × A has 9 elements among which are found (–1, 0) and (0, 1). Find the set A and the remaining elements of A × A.


If A = {1, 2} and B = {1, 3}, find A × B and B × A.


If A = {1, 2, 3} and B = {2, 4}, what are A × BB × AA × AB × B and (A × B) ∩ (B × A)?


If A and B are two set having 3 elements in common. If n(A) = 5, n(B) = 4, find n(A × B) and n[(A × B) ∩ (B × A)].


Let A = {1, 2, 3, 4} and R = {(ab) : a ∈ Ab ∈ Aa divides b}. Write R explicitly. 


Given A = {1, 2, 3}, B = {3, 4}, C ={4, 5, 6}, find (A × B) ∩ (B × C ).

 

If A = {2, 3}, B = {4, 5}, C ={5, 6}, find A × (B ∪ C), A × (B ∩ C), (A × B) ∪ (A × C).

 

If A = {1, 2, 3}, B = {4}, C = {5}, then verify that:

(i) A × (B ∪ C) = (A × B) ∪ (A × C)


If A = {1, 2, 3}, B = {3, 4} and C = {4, 5, 6}, find

(iii) A × (B ∪ C)


Prove that:

(i)  (A ∪ B) × C = (A × C) ∪ (B × C)

(ii) (A ∩ B) × C = (A × C) ∩ (B×C)

 

Find the domain of the real valued function of real variable: 

(ii)  \[f\left( x \right) = \frac{1}{x - 7}\]

 


Find the domain of the real valued function of real variable:  

(v)  \[f\left( x \right) = \frac{x^2 + 2x + 1}{x^2 - 8x + 12}\]

 


Find the domain of the real valued function of real variable:

(i) \[f\left( x \right) = \sqrt{x - 2}\]

 


Find the domain of the real valued function of real variable:

(iii) \[f\left( x \right) = \sqrt{9 - x^2}\]

 


Find the domain of the real valued function of real variable:

(iv)  \[f\left( x \right) = \frac{\sqrt{x - 2}}{3 - x}\]

 


Find the domain and range of the real valued function:

(ix)  \[f\left( x \right) = \frac{1}{\sqrt{16 - x^2}}\]


Find f + gf − gcf (c ∈ R, c ≠ 0), fg, \[\frac{1}{f}\text{  and } \frac{f}{g}\] in :

(a) If f(x) = x3 + 1 and g(x) = x + 1


Let f(x) = 2x + 5 and g(x) = x2 + x. Describe (i) f + g (ii) f − g (iii) fg (iv) f/g. Find the domain in each case.

 

If f(x) be defined on [−2, 2] and is given by \[f\left( x \right) = \begin{cases}- 1, & - 2 \leq x \leq 0 \\ x - 1, & 0 < x \leq 2\end{cases}\]  and g(x)

\[= f\left( \left| x \right| \right) + \left| f\left( x \right) \right|\] , find g(x).

 
 
 

Let A = {1, 2, 3, 4} and B = {5, 7, 9}. Determine is n (A × B) = n (B × A)?


Let A = {–1, 2, 3} and B = {1, 3}. Determine B × A


Let A = {–1, 2, 3} and B = {1, 3}. Determine A × A


State True or False for the following statement.

If A × B = {(a, x), (a, y), (b, x), (b, y)}, then A = {a, b}, B = {x, y}


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×