Advertisements
Advertisements
Question
The diameter of two circles are 28 cm and 24 cm. Find the circumference of the circle having its area equal to sum of the areas of the two circles.
Solution
Let R be the radius of the big circle.
The radii of two circles are
r1 = `"d"_1/(2) = (28)/(2) = 14"cm"`
and
r2 = `"d"_2/(2) = (24)/(2) = 12"cm"`
Now,
Area of big circle
= Sum of areas of circles of radii r1 and r2
⇒ πR2 = πr12 + πr22
⇒ R2 = r12 + r22
⇒ R2 = 142 + 122
⇒ R2 = 196 + 144
⇒ R2 = 340
⇒ R = 18.4
∴ Circumference of big circle
= 2πR
= `2 xx (22)/(7) xx 18.4`
= 115.65cm2.
APPEARS IN
RELATED QUESTIONS
In Fig. 6, find the area of the shaded region, enclosed between two concentric circles of radii 7 cm and 14 cm where ∠AOC = 40°. (use `pi = 22/7`)
The area of a circle inscribed in an equilateral triangle is 154 cm2. Find the perimeter of the triangle.
In the given figure, ABCD is a trapezium of area 24.5 cm2 , If AD || BC, ∠DAB = 90°, AD = 10 cm, BC = 4 cm and ABE is quadrant of a circle, then find the area of the shaded region.
If the sum of the circumferences of two circles with radii R1 and R2 is equal to the circumference of a circle of radius R, then ______.
The diameter of a right circular cylinder is 12 m and the slant height is 10 m. Find its curved surface area and the total surface area .
Find the circumference of a circle whose area is 81πcm2.
A wire in the form of a circle of radius 42cm. It is bent into a square. Determine the side of the square and compare the area of the regions enclosed in the two cases.
Find the perimeter of the given shape (Take π = `22/7`).
The diameter of the bullock cart wheel is 1.4 m. Find the distance covered by it in 150 rotations?
Value of π is ______ approximately.