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Question
The distance of the gate of a temple from its base is `sqrt(3)` times it height. Find the angle of elevation of the top of the temple.
Solution
Let AB be the temple and C be the position of its gate.
Let h be the height of the temple. Then,
AB= h
BC = Distance of the gate of temple from its base = `sqrt(3)`h
In ΔABC,
tanθ = `"AB"/"BC"`
⇒ `tanθ = h/(sqrt(3)h) = 1/sqrt(3)`
But , `tan30^circ = 1/sqrt(3)`
∴ θ = `30^circ`
Thus , the angle of elevation of the top of the temple is `30^circ`.
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