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The following experimental rate data were obtained for a reaction carried out at 25°C: A(g)+B(g)⟶C(g)+A(g) What are the orders with respect to A(g) and B(g)? - Chemistry

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Question

The following experimental rate data were obtained for a reaction carried out at 25°C:

\[\ce{A_{(g)} + B_{(g)} -> C_{(g)} + A_{(g)}}\]

Initial [A(g)]/mol dm−3 Initial [B(g)]/mol dm−3 Initial rate/mol dm−3s−1
3.0 × 10−2 2.0 × 10−2 1.89 × 10−4
3.0 × 10−2 4.0 × 10−2 1.89 × 10−4
6.0 × 10−2 4.0 × 10−2 7.56 × 10−4

What are the orders with respect to A(g) and B(g)?

Options

  • Order with respect to A(g) Order with respect to B(g)
    Zero Second
  • Order with respect to A(g) Order with respect to B(g)
    First Zero
  • Order with respect to A(g) Order with respect to B(g)
    Second Zero
  • Order with respect to A(g) Order with respect to B(g)
    Second First
MCQ

Solution

Order with respect to A(g) Order with respect to B(g)
Second Zero

Explanation:

Rate of reaction R = k[A]n [B]m

where n and m are the order of reaction w.r.t

A and B from the given table change A(g), keeping B(g) constant,

R1 = k[3 × 10−2]n [4 × 10−2]m = 1.89 × 10−4

R2 = k[6 × 10−2]n [4 × 10−2]m = 7.56 × 10−4

`(1/2)^"n" = 1/4` ⇒ n  = 2

Change B(g), keeping A(g) constant,

R1 = k[3 × 10−2]n [2 × 10−2]m = 1.89 × 10−4

R2 = k[3 × 10−2]n [4 × 10−2]m = 1.89 × 10−4

`(1/2)^"m"` = 1 ⇒ m  = 0

Therefore the order of reaction with respect to A(g) and B(g) will be second order and zero order, respectively.

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