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Question
The function f and g are defined by f(x) = 6x + 8; g(x) = `(x - 2)/3`
Calculate the value of `"gg" (1/2)`
Solution
`"gg" (1/2) = "g"["g"(1/2)]`
= `"g"[1/2 - 2 ÷ 3]`
= `"g"[(1 - 4)/2 ÷ 3]`
= `"g"[(-3)/2 xx 1/3]`
= `"g"[- 1/2]`
= `[- 1/2 - 2 ÷ 3]`
= `[(-1 - 4)/2 ÷ 3]`
= `[(-5)/2 xx 1/3]`
`"gg" (1/2) = - 5/6`
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