Advertisements
Advertisements
Question
The line through the points (– 2, 6) and (4, 8) is perpendicular to the line through the points (8, 12) and (x, 24). Find the value of x.
Solution
Find the slope of the line joining the point (– 2, 6) and (4, 8)
Slope of line (m1) = `(y_2 - y_1)/(x_2 - x_1)`
= `(8- 6)/(4 + 2) = 2/6 = 1/3`
Find the slope of the line joining the points (8, 12) and (x, 24)
Slope of a line (m2) = `(24 - 12)/(x - 8) = 12/(x - 8)`
Since the two lines are perpendicular.
m1 × m2 = – 1
`1/3 xx 12/(x - 8)` = – 1
⇒ `12/(3(x - 8))` = – 1
– 1 × 3(x – 8) = 12
– 3x + 24 = 12
⇒ – 3x = 12 – 24
– 3x = – 12
⇒ x = `12/3` = 4
∴ The value of x = 4
APPEARS IN
RELATED QUESTIONS
What is the slope of a line whose inclination with positive direction of x-axis is 0°
What is the inclination of a line whose slope is 0
Find the slope of a line joining the points
(sin θ, – cos θ) and (– sin θ, cos θ)
The line through the points (– 2, a) and (9, 3) has slope `-1/2` Find the value of a.
Show that the given points form a parallelogram:
A(2.5, 3.5), B(10, – 4), C(2.5, – 2.5) and D(– 5, 5)
Let A(3, – 4), B(9, – 4), C(5, – 7) and D(7, – 7). Show that ABCD is a trapezium.
A quadrilateral has vertices at A(– 4, – 2), B(5, – 1), C(6, 5) and D(– 7, 6). Show that the mid-points of its sides form a parallelogram.
The slope of the line which is perpendicular to a line joining the points (0, 0) and (− 8, 8) is
Without using distance formula, show that the points (−2, −1), (4, 0), (3, 3) and (−3, 2) are vertices of a parallelogram
Find the equation of a line passing through the point of intersection of the lines 4x + 7y – 3 = 0 and 2x – 3y + 1 = 0 that has equal intercepts on the axes.