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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

The line through the points (– 2, 6) and (4, 8) is perpendicular to the line through the points (8, 12) and (x, 24). Find the value of x. - Mathematics

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Question

The line through the points (– 2, 6) and (4, 8) is perpendicular to the line through the points (8, 12) and (x, 24). Find the value of x.

Sum

Solution

Find the slope of the line joining the point (– 2, 6) and (4, 8)

Slope of line (m1) = `(y_2 - y_1)/(x_2 - x_1)`

= `(8- 6)/(4 + 2) = 2/6 = 1/3`

Find the slope of the line joining the points (8, 12) and (x, 24)

Slope of a line (m2) = `(24 - 12)/(x - 8) = 12/(x - 8)`

Since the two lines are perpendicular.

m1 × m2 = – 1

`1/3 xx 12/(x - 8)` = – 1

⇒ `12/(3(x - 8))` = – 1

– 1 × 3(x – 8) = 12

– 3x + 24 = 12

⇒ – 3x = 12 – 24

 – 3x = – 12

⇒ x = `12/3` = 4

∴ The value of x = 4

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Inclination of a Line
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Chapter 5: Coordinate Geometry - Exercise 5.2 [Page 220]

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Samacheer Kalvi Mathematics [English] Class 10 SSLC TN Board
Chapter 5 Coordinate Geometry
Exercise 5.2 | Q 8 | Page 220
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