Question

The link CD of the mechanism shown in Figure 7 is rotating in counterclockwise direction at an angular velocity of 5 rad/s. For the given instance, determine the angular velocity of link AB.

Answer 1

In ΔEBC,
Using Sine rule,

`(EB)/(sin(75)) -  (BC)/(sin(45) )-   (CE)/(sin(60)`

`EB = (200 xx sin (75))/(sin(45)) = 0.27 m               CE = (200 xx sin (60))/sin(45) = 0.24m`

ω_CD = V_C x CD
`V_C = 5/0.1= 50` m/s
`ω_(BC) = V_C xx  CE = 50 x 0.24 = 12` rad/s
`ω_(BC) = V_B xx EB`

`V_B = 12/(0.27) = 44.44`m/s

`ω_AB = V_B xx AB = 44.44 xx 0.15 = 6.666` rad/s

The angular velocity of link AB is 6.666 rad/s.