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The marks obtained by 19 students of a class are given below: 27, 36, 22, 31, 25, 26, 33, 24, 37, 32, 29, 28, 36, 35, 27, 26, 32, 35 and 28. Find: Median Lower quartile Upper quartile - Mathematics

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Question

The marks obtained by 19 students of a class are given below:

27, 36, 22, 31, 25, 26, 33, 24, 37, 32, 29, 28, 36, 35, 27, 26, 32, 35 and 28.

Find:

  1. Median
  2. Lower quartile
  3. Upper quartile
  4. Inter-quartile range
Sum

Solution

Arranging in ascending order: 

22, 24, 25, 26, 26, 27, 27, 28, 28, 29, 31, 32, 32, 33, 35, 35, 36, 36, 37

i. Median = `((n + 1)/2)^(th)` term

= `((19 + 1)/2)^(th)`

= `(20/2)^(th)`

= 10th 

= 29

ii. Lower quartile (Q1) = `((n + 1)/4)^(th)`

= `((19 + 1)/4)^(th)`

= 5th

= 26

iii. Upper quartile (Q3) = `((3(n + 1))/4)^(th)`

= `((3(19 + 1))/4)^(th)`

= 3 × 5th 

= 15th

= 35

iv. Inter-quartile range = Q3 – Q1

= 35 – 26

= 9

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Chapter 24: Measure of Central Tendency(Mean, Median, Quartiles and Mode) - Exercise 24 (C) [Page 372]

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Selina Mathematics [English] Class 10 ICSE
Chapter 24 Measure of Central Tendency(Mean, Median, Quartiles and Mode)
Exercise 24 (C) | Q 3 | Page 372

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