English

The Perimeter of a Rhombus is 46 Cm. If the Height of the Rhombus is 8 Cm; Find Its Area. - Mathematics

Advertisements
Advertisements

Question

The perimeter of a rhombus is 46 cm. If the height of the rhombus is 8 cm; find its area.

Sum

Solution

Let a be the length of each side of the rhombus.
4a = perimeter
4a = 46
a = 11.5 cm

We know that,
Area = Base x Height
         = 11.5 x 8 
         = 92 sq.cm

shaalaa.com
  Is there an error in this question or solution?
Chapter 20: Area and Perimeter of Plane Figures - Exercise 20 (B) [Page 255]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 20 Area and Perimeter of Plane Figures
Exercise 20 (B) | Q 21 | Page 255

RELATED QUESTIONS

The distance between parallel sides of a trapezium is 15 cm and the length of the line segment joining the mid-points of its non-parallel sides is 26 cm. Find the area of the trapezium.


The area of a rectangular is 640 m2. Taking its length as x cm; find in terms of x, the width of the rectangle. If the perimeter of the rectangle is 104 m; find its dimensions.


The perimeter of a rhombus is 52 cm. If one diagonal is 24 cm; find:
(i) The length of its other diagonal,
(ii) Its area.


The area of a rhombus is 216 sq. cm. If it's one diagonal is 24 cm; find:
(i) Length of its other diagonal,
(ii) Length of its side,
(iii) The perimeter of the rhombus.


The diagram, given below, shows two paths drawn inside a rectangular field 80 m long and 45 m wide. The widths of the two paths are 8 m and 15 m as shown. Find the area of the shaded portion. 


A quadrilateral field of unequal has a longer diagonal with 140m. The perpendiculars from opposite vertives upon this diagonal are 20m and 14m. Find the area of the field.


The floor of a room is of size 6 m x 5 m. Find the cost of covering the floor of the room with 50 cm wide carpet at the rate of Rs.24.50 per metre. Also, find the cost of carpeting the same hall if the carpet, 60 cm, wide, is at the rate of Rs.26 per metre.


Find the area of a quadrilateral field whose sides are 12m, 9m, 18m and 21m respectively and the angle between the first two sides is a right angle. Take the value of `sqrt(6)` as 2.5.


Find the area of the quadrilateral whose vertices are at (– 9, 0), (– 8, 6), (– 1, – 2) and (– 6, – 3)


If vertices of a quadrilateral are at A(– 5, 7), B(– 4, k), C(– 1, – 6) and D(4, 5) and its area is 72 sq. units. Find the value of k.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×