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Question
The perimeter of the quadrant of a circle is 25 cm. Find its area.
Solution
Let the radius of the circle be r
Now, Perimeter of quadrant`=1/4(2pi"r")+2"r"`
`=> 25 = 1/2xx22/7xx"r"+2"r"`
`=> 25 = (25"r")/7`
⇒ r = 7 cm
Area of quadrant `= 1/4pi"r"^2=1/4xx22/7xx7xx7=38.5 "cm"^2`
Hence,the area of quadrant is 38.5 cm2
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