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Question
The perimeter of a sector of a circle of radius 5.6 cm is 27.2 cm. Find the area of the sector.
Solution
Let O be the centre of the circle with radius 5.6 cm and OACB be its sector with perimeter 27.2 cm.
Thus, we have:
OA + OB + arc AB = 27.2
⇒ 5.6 + 5.6 + arc AB = 27.2
⇒ arc AB = 16 cm
Now,
Area of the sector OACBO` = (1/2xx"Radius"xxl)"square Units"`
`=(1/(2)5.6xx16)"cm"^20`
= 44.8 cm2
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