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Question
A race track is in the form of a rig whose inner circumference is 352 m and outer circumference is 396 m. Find the width and the area of the track.
Solution
Let r m and R m be the radii of the inner and outer tracks.
Now,
Circumference of the outer track = 2πR
`=> 396 = 2xx22/7xx"R"`
`=> "R" = (396xx7)/44`
⇒ R = 63
Circumference of the inner track = 2πr
`=> 352 = 2xx22/7xx"r"`
`=> r = (352xx7)/44 `
⇒ r = 56
Width of the track = Radius of the outer track -- Radius of the inner track
= 63 - 56
= 7 m
Area of the outer circle = πR2
`=22/7xx56xx56`
= 12474 m2
Area of the inner circle = πR2
`=22/7xx56xx56`
= 9856 m2
Area of the track = 12474 - 9856
= 2618 m2
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