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Question
The ratio of the base area and the curved surface of a conical tent is 40: 41. If the height is 18 m, Find the air capacity of the tent in terms of n.
Solution
Given: `"base area"/"curved surface" = 40/41`
⇒ `(πr^2)/(πrsqrt(h^2 + r^2)) = 40/41` ...( Where h is the height and r is the radius of conical tent)
⇒ `(r)/(sqrt(18^2 + r^2)) = 40/41` ....( ∵ h = 18 m)
⇒ r = 80 m
∴ Air capacity = `1/3 π (80)^2 xx 18`
Air capacity = 38,400 π cu m.
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