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Question
The scores (out of 100) obtained by 33 students in a mathematics test are as follows:
69, 48, 84, 58, 48, 73, 83, 48, 66, 58, 84, 66, 64, 71, 64, 66, 69, 66, 83, 66, 69, 71, 81, 71, 73, 69, 66, 66, 64, 58, 64, 69, 69
Represent this data in the form of a frequency distribution.
Solution
The number of students who have the same marks in mathematics is called the frequency of that mark.
A frequency distribution table for the given data is given below:
| Scores | Tally marks | Frequency |
| 48 | `bb|bb|bb|` | 3 |
| 58 | `bb|bb|bb|` | 3 |
| 64 | `bb|bb|bb|bb|` | 4 |
| 66 | `\cancel(bb|bb|bb|bb|) bb|bb|` | 7 |
| 69 | `\cancel(bb|bb|bb|bb|) bb|` | 6 |
| 71 | `bb|bb|bb|` | 3 |
| 73 | `bb|bb|` | 2 |
| 81 | `bb|` | 1 |
| 83 | `bb|bb|` | 2 |
| 84 | `bb|bb|` | 2 |
| Total | 33 |
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| Below 35 | 78 |
| Below 40 | 183 |
| Below 45 | 294 |
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| Below 55 | 543 |
| Below 60 | 621 |
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In the class intervals 10-20, 20-30, 20 is taken in
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81, 72, 90, 90, 86, 85, 92, 70, 71, 83, 89, 95, 85, 79, 62
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For drawing a frequency polygon of a continous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abcissae are respectively ______.
Convert the given frequency distribution into a continuous grouped frequency distribution:
| Class interval | Frequency |
| 150 – 153 | 7 |
| 154 – 157 | 7 |
| 158 – 161 | 15 |
| 162 – 165 | 10 |
| 166 – 169 | 5 |
| 170 – 173 | 6 |
In which intervals would 153.5 and 157.5 be included?
The following are the marks (out of 100) of 60 students in mathematics.
16, 13, 5, 80, 86, 7, 51, 48, 24, 56, 70, 19, 61, 17, 16, 36, 34, 42, 34, 35, 72, 55, 75, 31, 52, 28, 72, 97, 74, 45, 62, 68, 86, 35, 85, 36, 81, 75, 55, 26, 95, 31, 7, 78, 92, 62, 52, 56, 15, 63, 25, 36, 54, 44, 47, 27, 72, 17, 4, 30.
Construct a grouped frequency distribution table with width 10 of each class, in such a way that one of the classes is 10 – 20 (20 not included).
