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Question
The sum of the polynomials p(x) = x3 – x2 – 2, q(x) = x2 – 3x + 1
Options
x3 – 3x – 1
x3 + 2x2 – 1
x3 – 2x2 – 3x
x3 – 2x2 + 3x – 1
Solution
x3 – 3x – 1
Explanation;
Hint:
p(x) + q(x) = (x3 – x2 – 2) + (x2 – 3x + 1)
= x3 – x2 – 2 + x2 – 3x + 1
= x3 – 3x – 1
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