Find the value of the polynomial f(y) = 6y – 3y2 + 3 at y = –1 - Mathematics

Find the value of the polynomial f(y) = 6y – 3y² + 3 at y = –1

Sum

When y = –1

f(y) = 6y – 3y² + 3

f(–1) = 6(–1) – 3(–1)² + 3

= – 6 – 3 + 3

= – 6

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Value of a Polynomial

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Chapter 3: Algebra - Exercise 3.2 [Page 91]

Chapter 3 Algebra
Exercise 3.2 | Q 1. (ii) | Page 91

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