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Question
The vertices of a triangle are A(3, 4), B(2, 0), and C(−1, 6). Find the equation of the line containing side BC.
Solution
Vertices of ΔABC are A(3, 4), B(2, 0) and C(−1, 6).
Equation of the line in two point form is
`(y - y_1)/(y_2 - y_1) = (x - x_1)/(x_2 - x_1)`
∴ The equation of the side BC is
`(y - 0)/(6 - 0) = (x - 2)/(-1 - 2)`
∴ `y/6 = (x - 2)/(-3)`
∴ −3y = 6x − 12
∴ 6x + 3y − 12 = 0 ...(∵ both side divide by 3)
∴ 2x + y − 4 = 0
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