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Question
The vertices of a triangle are A(3, 4), B(2, 0) and C(1, 6). Find the equations of side BC
Solution
Vertices of ΔABC are A(3, 4), B(2, 0) and C(1, 6).
Equation of a line in two point form is
`(y - y_1)/(y_2 - y_1) = (x - x_1)/(x_2 - x_1)`
∴ The equation of the side BC is
`(y - 0)/(6 - 0) = (x - 2)/(1 - 2) ...[("B" = (x_1,y_1) = (2, 0)),("C" = (x_2,y_2) = (1, 6))]`
∴ `y/6 = (x - 2)/(-1)`
-y = 6 (x – 2)
-y = 6x - 12
∴ 6x + y - 12 = 0
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