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Karnataka Board PUCPUC Science 2nd PUC Class 12

Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. Determine the charge on each capacitor if the combination is connected to a 100 V supply. - Physics

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Question

Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. Determine the charge on each capacitor if the combination is connected to a 100 V supply.

Numerical

Solution

Supply voltage, V = 100 V

The voltage through all the three capacitors is same = V = 100 V

Charge on a capacitor of capacitance C and potential difference V is given by the relation,

q = VC …....(i)

For C = 2 pF,

Charge = VC = 100 × 2 = 200 pC = 2 × 10−10 C

For C = 3 pF,

Charge = VC = 100 × 3 = 300 pC = 3 × 10−10 C

For C = 4 pF,

Charge = VC = 100 × 4 = 400 pC = 4 × 10−10 C

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Chapter 2: Electrostatic Potential and Capacitance - Exercise [Page 87]

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NCERT Physics [English] Class 12
Chapter 2 Electrostatic Potential and Capacitance
Exercise | Q 7. (b) | Page 87
NCERT Physics [English] Class 12
Chapter 2 Electrostatic Potential and Capacitance
Exercise | Q 2.7 (b) | Page 86

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