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Question
To fill 12 vacancies there are 25 candidates of which 5 are from scheduled castes. If 3 of the vacancies are reserved for scheduled caste candidates while the rest are open to all, the number of ways in which the selection can be made is 5C3 × 20C9.
Options
True
False
Solution
This statement is False.
Explanation:
Number of ways to select 3 scheduled caste candidate out of 5 = 5C3
We have to select 9 other candidates out of 22.
So the number of ways = 22C9
Required number of selection = 5C3 × 22C9
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