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Question
Triangles ABC and DEF are similar.
If area (ΔABC) = 16 cm2, area (ΔDEF) = 25 cm2 and BC = 2·3 cm find EF.
Solution
We have
area (ΔABC) = 16 cm2
area (ΔDEF) = 25 cm2
and BC = 2·3 cm
Since , `"area (ΔABC)"/"area (ΔDEF)" = "BC"^2/"EF"^2`
⇒ `(16)/(25) = (2.3)^2/"EF"^2`
⇒ `(2·3)/"EF" = (4)/(5)`
⇒ 4EF = 5 x 2·3
⇒ EF = `(11.5)/(4)`
⇒ EF = 2·875 cm.
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