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Question
In the figure, given below, straight lines AB and CD intersect at P; and AC || BD. Prove that: ΔAPC and ΔBPD are similar.
Solution
In ΔAPC and ΔBPD,
∠APC = ∠BPD ...(Vertically opposite angles)
∠ACP = ∠BDP ...(Alternate angles since AC || BD)
ΔAPC ∼ ΔBPD ...(AA criterion for similarity)
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