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Question
Two parallel lines are cut by transversal. If one angle of a pair of corresponding angles can be represented by 42° less than three times the other. Find the corresponding angles
Solution
We know that the corresponding angles are equal.
Let one of the corresponding angles be x.
Then the other will be 3x – 42°.
∴ 3x − 42° = x°
3x − 42° + 42° = x° + 42°
3x° = x + 42°
3x° − x° = x + 42° − x
2x = 42°
x = `42/2`
x = 21°
∴ The corresponding angles are 21° each
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