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Question
Use ruler and compasses only for this question:
(i) Construct A ABC, where AB = 3.5 cm, BC = 6 cm and ∠ ABC = 60°.
(ii) Construct the locus of points inside the triangle which are equidistant from BA and BC.
(iii) Construct the locus of points inside the triangle which are equidistant from B and C.
(iv) Mark the point P which is equidistant from AB, BC, and also equidistant from B and C. Measure and record the length of PB.
Solution
(i) See Figure,
(ii) Inside the triangle point, P is equidistant from BA and BC.
(iii) Line EF is the locus of points inside the triangle which are equidistant from B and C.
(iv) PB = 3.5 cm.
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