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Question
Use the mirror equation to deduce that the virtual image produced by a convex mirror is always diminished in size and is located between the focus and the pole.
Solution
For a convex mirror, the focal length (f) is positive.
∴ f > 0
When the object is placed on the left side of the mirror, the object distance (u) is negative,
∴ u < 0
For image distance v, we have the mirror formula:
`1/"v" + 1/"u" = 1/"f"`
`1/"v" = 1/"f" - 1/"u"`
But we have u < 0
∴ `1/"v" > 1/"f"`
v < f
Hence, the image formed is diminished and is located between the focus (f) and the pole.
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