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A(– 2, 3, 4), B(1, 1, 2) and C(4, –1, 0) are three points. Find the Cartesian equations of the line AB and show that points A, B, C are collinear. - Mathematics and Statistics

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प्रश्न

A(– 2, 3, 4), B(1, 1, 2) and C(4, –1, 0) are three points. Find the Cartesian equations of the line AB and show that points A, B, C are collinear.

योग

उत्तर

We find the cartesian equations of the line AB.

The cartesian equations of the line passing through the points (x1, y1, z1) and  (x2, y2, z2) are

`(x - x_1)/(x_2 - x_1) = (y - y_1)/(y_2 - y_1) = (z - z_1)/(z_2 - z_1)`

Here, (x1, y1, z1) ≡ (−2, 3, 4) and (x2, y2, z2) ≡ (1, 1, 2)

∴  The required cartesian equations of the line AB are

`(x - (-2))/(1 - (-2)) = (y - 3)/(1 - 3) = (z - 4)/(2 - 4)`

∴ `(x + 2)/(1 + 2) = (y - 3)/(-2) = (z - 4)/(-2)`

∴ `(x + 2)/(3) = (y - 3)/(-2) = (z - 4)/(-2)`

C = (4, −1, 0)

For x = 4, `(x + 2)/(3) = (4 + 2)/(3)` = 2

For y = –1, `(y - 3)/(-2) = (-1 - 3)/(-2)` = 2

For z = 0, `(z - 4)/(-2) = (0 - 4)/(-2)` = 2

∴ The coordinates of C satisfy the equations of line AB.

∴ C lies on the line passing through A and B.

Hence, A, B, C are collinear.

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Vector and Cartesian Equations of a Line
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Line and Plane - Exercise 6.1 [पृष्ठ २००]

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