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A and B are events such that P(A) = 0.4, P(B) = 0.3 and P(A ∪ B) = 0.5. Then P(B′ ∩ A) equals ______. - Mathematics

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प्रश्न

A and B are events such that P(A) = 0.4, P(B) = 0.3 and P(A ∪ B) = 0.5. Then P(B′ ∩ A) equals ______.

विकल्प

  • `2/3`

  • `1/2`

  • `3/10`

  • `1/5`

MCQ
रिक्त स्थान भरें

उत्तर

A and B are events such that P(A) = 0.4, P(B) = 0.3 and P(A ∪ B) = 0.5. Then P(B′ ∩ A) equals `1/5`.

Explanation:

Given that: P(A) = 0.4, P(B) = 0.3 and P(A ∪ B) = 0.5

P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

0.5 = 0.4 + 0.3 – P(A ∩ B)

P(A ∩ B) = 0.4 + 0.3 – 0.5 = 0.2

∴ P(B' ∩ A) = P(A) – P(A ∩ B)

= 0.4 – 0.2

= 0.2

= `1/5`

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अध्याय 13: Probability - Exercise [पृष्ठ २८०]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 13 Probability
Exercise | Q 63 | पृष्ठ २८०

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