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A copper wire, 3 mm in diameter, is wound about a cylinder whose length is 12 cm, and diameter 10 cm, so as to cover the curved surface of the cylinder. - Mathematics

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प्रश्न

A copper wire, 3 mm in diameter, is wound about a cylinder whose length is 12 cm, and diameter 10 cm, so as to cover the curved surface of the cylinder. Find the length and mass of the wire, assuming the density of copper to be 8.88 g per cm3.

उत्तर

It can be observed that 1 round of wire will cover 3 mm height of cylinder.

Number of rounds = Height of cylinder/Diameter of wire

= 12/0.3 = 40 rounds

Length of wire required in 1 round = Circumference of base of cylinder

= 2πr = 2π × 5 = 10π

Length of wire in 40 rounds = 40 × 10π

`= (400xx22)/7 = 8800/7`

= 1257.14 cm = 12.57 m

Radius of wire = 0.3/2 = 0.15 cm

Volume of wire = Area of cross-section of wire × Length of wire

= π(0.15)2 × 1257.14

= 88.898 cm3

Mass = Volume × Density

= 88.898 × 8.88

= 789.41 gm

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अध्याय 13: Surface Areas and Volumes - Exercise 13.5 [पृष्ठ २५८]

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एनसीईआरटी Mathematics [English] Class 10
अध्याय 13 Surface Areas and Volumes
Exercise 13.5 | Q 1 | पृष्ठ २५८

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