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प्रश्न
A cubical block of side 10 cm is surmounted by a hemisphere. What is the largest diameter that the hemisphere can have? Find the cost of painting the total surface area of the solid so formed, at the rate of Rs. 5 per 100 sq. cm. [Use π = 3.14]
उत्तर
Side of the cubical block, a = 10 cm
Longest diagonal of the cubical block = a√3 = 10√3 cm
Since the cube is surmounted by a hemisphere, therefore the side of the cube should be equal to the diameter of the hemisphere.
Diameter of the sphere = 10 cm
Radius of the sphere, r = 5 cm
Total surface area of the solid = Total surface area of the cube – Inner cross-section area of the hemisphere + Curved surface area of the hemisphere
`=6a^2-pir^2+2pir^2`
`=6a^2+pir^2`
`=6xx(10)^2+3.14xx5^2`
`=600+78.5=678.5 cm^2`
Total surface area of the solid = 678.5 cm2
Cost of painting 100 cm2 = Rs. 5
Cost of painting 1 cm2 = Rs.5/100
Cost of painting the total surface area of the solid =(5/100)× 678.5 = Rs. 33.925 ≈ Rs. 34.
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