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A Rhombus Sheet, Whose Perimeter is 32 M and Whose One Diagonal is 10 M Long, is Painted on Both Sides at the Rate of Rs 5 per M2. Find the Cost of Painting. - Mathematics

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A rhombus sheet, whose perimeter is 32 m and whose one diagonal is 10 m long, is painted on both sides at the rate of Rs 5 per m2. Find the cost of painting.

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Given that,
Perimeter of a rhombus = 32 m
We know that,
Perimeter of rhombus = 4 × side
⇒ 49 = 32m
⇒ a = 8 m
Let AC = 10 = OA = `1/2`ЁЭР┤ЁЭР╢
= `1/2`×10
= 5ЁЭСЪ

By using Pythagoras theorem:

∴`OB^2=AB^2-OA^2`

`⇒OB=sqrt(AB^2-OA^2)`

`⇒OB=sqrt(8^2-5^2)`

`⇒OB=sqrt(64-25)`

`⇒OB=sqrt(39m)`

Now, BD = 2OB = 2√39ЁЭСЪ

∴ Area of sheet = `1/2`×ЁЭР╡ЁЭР╖×ЁЭР┤ЁЭР╢=`1/2`×2`sqrt(39)xx10sqrt(39)m^2`

∴ Cost of printing on both sides at the rate of Rs 5 per `m^2` = Rs 2 ×10`sqrt(39)`×5
= Rs. 625.00

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рдЕрдзреНрдпрд╛рдп 17: HeronтАЩs Formula - Exercise 17.2 [рдкреГрд╖реНрда резреп]

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рдЖрд░рдбреА рд╢рд░реНрдорд╛ Mathematics [English] Class 9
рдЕрдзреНрдпрд╛рдп 17 HeronтАЩs Formula
Exercise 17.2 | Q 6 | рдкреГрд╖реНрда резреп

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