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प्रश्न
A speaks the truth in 60% of the cases, while B is 40% of the cases. In what percent of cases are they likely to contradict each other in stating the same fact?
उत्तर
A speaks truth `P(A) = 60/100`, `P(A') = 40/100`
B speaks truth `P(B) = 40/100`, `P(B') = 60/100`
they contradict each other = `P(A).(B') + P(A') . P(B)`
`= 60/10 xx 60/100 + 40/100 xx 40/100`
`= (3600+1600)/10000`
`= 5200/10000`
`= 52/100`
% of cases they likey to contradict each other = `52/100 xx 100 = 52%`
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