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A vessel is in the form of an inverted cone. Its height is 8 cm and the radius of its top, which is open, is 5 cm. It is filled with water up to the brim. When lead shots, each of which is a sphere of - Mathematics

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प्रश्न

A vessel is in the form of an inverted cone. Its height is 8 cm and the radius of its top, which is open, is 5 cm. It is filled with water up to the brim. When lead shots, each of which is a sphere of radius 0.5 cm, are dropped into the vessel, one-fourth of the water flows out. Find the number of lead shots dropped in the vessel.

योग

उत्तर

 
Height of cone = 8 cm

Radius = 5 cm 

Volume = `1/3pir^2h` 

= `1/3 xx 22/7 xx 5 xx 5 xx 8  cm^3` 

= `4400/21 cm^3` 

Therefore, volume of water that flowed out

= `1/4 xx 4400/21 cm^3` 

= `1100/21 cm^3` 

Radius of each ball = 0.5 cm = `1/2` cm  

Volume of a ball = `4/3pir^3` 

= `4/3 xx 22/7 xx 1/2 xx 1/2 xx 1/2 cm^3`  

= `11/21 cm^3` 

Therefore, No. of balls = `1100/21 ÷ 11/21 = 100` 

Hence, number of lead balls = 100

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अध्याय 20: Cylinder, Cone and Sphere - Exercise 20 (E) [पृष्ठ ३१२]

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 20 Cylinder, Cone and Sphere
Exercise 20 (E) | Q 5 | पृष्ठ ३१२

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