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प्रश्न
Angle ABC = 60° and BA = BC = 8 cm. The mid-points of BA and BC are M and N respectively. Draw and describe the locus of a point which is:
- equidistant from BA and BC.
- 4 cm from M.
- 4 cm from N.
Mark the point P, which is 4 cm from both M and N, and equidistant from BA and BC. Join MP and NP, and describe the figure BMPN.
उत्तर
- Draw an angle of 60° with AB = BC = 8 cm
- Draw the angle bisector BX of ∠ABC
- With centre M and N, draw circles of radius equal to 4 cm, which intersects each other at P. P is the required point.
- Join MP, NP
BMPN is a rhombus since MP = BM = NB = NP = 4 cm
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संबंधित प्रश्न
Use ruler and compasses only for this question:
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II. Construct the locus of points inside the triangle which are equidistant from BA and BC.
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