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Evaluate : Sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3) - Mathematics

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प्रश्न

Evaluate :
`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`

योग

उत्तर

`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`

= `sqrt( 1/2 xx 1/2 ) + ( 0.1 xx 0.1 )^(-1/2) - ( 3 xx 3 xx 3)^(2/3)`

= `1/2 + [(0.1)^2]^(-1/2) - (3^2)^(2/3)`

= `1/2 + ( 0.1 )^( 2 xx (-1/2)) - 3 xx ( 3 xx 2/3 )`

= `1/2 + ( 0.1 )^( - 1) - 3^2`

= `1/2 + 1/0.1 - 9`

= `1/2 + 10/1 - 9`

= `[ 1 + 20 - 18 ]/2`

= `3/2`

= `1 1/2`

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Laws of Exponents
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Indices (Exponents) - Exercise 7 (A) [पृष्ठ ९८]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 7 Indices (Exponents)
Exercise 7 (A) | Q 3.1 | पृष्ठ ९८
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