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Examine the consistency of the system of equations. x + 3y = 5 2x + 6y = 8 - Mathematics

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प्रश्न

Examine the consistency of the system of equations.

x + 3y = 5

2x + 6y = 8

योग

उत्तर

Let, A `= [(1,3),(2,6)], X = [(x),(y)], B = [(5),(8)]`

Then the given system of equations can be written as,

`[(1,3),(2,6)][(x),(y)] = [(5),(8)]`

Now, `abs A = [(1,3),(2,6)] = 1 xx 6 - 2 xx 3 = 0`

cofactors of the elements of `abs A` are respectively

`A_11 = 6, A_12 = -2, A_21 = -3, A_22 = 1`

`therefore adj A = [(6,-2),(-3,1)] = [(6,-3),(-2,1)]`

`=> (adj A) B = [(6,-3),(-2,1)] [(5),(8)] = [(30 - 24),(-10 + 8)] = [(6),(-2)] ne 0`

`abs A = 0  और  (adj A) "B" ne 0`

Therefore, the given system of equations is inconsistent.

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अध्याय 4: Determinants - Exercise 4.6 [पृष्ठ १३६]

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एनसीईआरटी Mathematics [English] Class 12
अध्याय 4 Determinants
Exercise 4.6 | Q 3 | पृष्ठ १३६

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