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प्रश्न
Explain the Catenation power.
उत्तर
- Carbon has a unique ability to form strong covalent bonds with other carbon atoms; this results in the formation of big molecules. This property of carbon is called catenation power.
- Due to the catenation power of carbon, the compounds formed may have long straight chains of carbon, branched chains of carbon or rings of carbon.
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संबंधित प्रश्न
Write answer as directed.
Give any four functional groups containing oxygen as the heteroatom in it. Write name and structural formula of one example each.
Give names of three functional groups containing three different hetero atoms. Write name and structural formula of one example each.
Find the odd one out and give its explanation.
Write the molecular formula of the given compound.
Acetone
Write the molecular formula of the given compound.
Isobutane
Match the columns.
| Group A | Group B |
| 1. Straight chain hydrocarbon | a) Benzene |
| 2. Branched chain hydrocarbon | b) Propyne |
| 3. Cyclic hydrocarbon | c) Isobutylene |
Cyclohexane is a branched chain type of hydrocarbon.
In LPG, butane is a flammable component.
Explain the concept of heteroatoms with the help of examples.
Distinguish between:
Saturated hydrocarbons - Unsaturated hydrocarbons
Distinguish between:
Open chain hydrocarbons - Closed chain hydrocarbons
Distinguish between:
Alkane - Alkene
Write a short note.
Catenation power
Complete the given chart with writing the correct functional group of carbon compounds.
(Ester, Aldehyde, Ketone, Carboxylic acid, Alcohol, Ether)
| -O-H | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-H} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\\ ||\\ \ce{-C-} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\phantom{.....}\\ ||\phantom{.....}\\ \ce{-C-O-H} \end{array}\] |
|
| -O- | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-O} \end{array}\] |
|
|
\[\begin{array}{cc} |
Match the following.
| Functional group –OH | - | Benzene |
| Heterocyclic | - | Potassium stearate |
| Unsaturated | - | Alcohol |
| Soap | - | Furan |
| Carbocyclic | - | Ethene |
Chlorine reacts with saturated hydrocarbons at room temperature in the
Which of the following is not a straight chain hydrocarbon?
Consider the following organic compounds:
| (i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ |\phantom{....}|\phantom{....}|\\ \ce{H - C - C - C = O}\\ |\phantom{....}|\phantom{.....}\\ \ce{H}\phantom{....}\ce{H}\phantom{.....} \end{array}\] |
(ii) \[\begin{array}{cc} \phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\ \phantom{....}|\phantom{....}|\phantom{....}\\ \ce{H - C - C = O}\\|\phantom{.....}\\ \ce{H}\phantom{.....}\end{array}\] |
- Name the functional group present in these compounds.
- Write the general formula for the compounds of this functional group.
- State the relationship between these compounds and draw the structure of any other compound having a similar functional group.
One variety of household fuel is a mixture of propane (60%) and butane (40%). If 20 litres of this mixture is burnt, find the total volume of carbon dioxide added to the atmosphere. The combination reactions can be represented as:
\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]
\[\ce{2C4H10 +13O2 -> 8CO2 + 10H2O}\]
