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Write the molecular formula of the given compound. Acetone - Science and Technology 1

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प्रश्न

Write the molecular formula of the given compound.

Acetone

एक पंक्ति में उत्तर

उत्तर

Acetone- C3H6O

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अध्याय 9: Carbon compounds - Answer in one sentence.

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संबंधित प्रश्न

Write answer as directed.
Give any four functional groups containing oxygen as the heteroatom in it. Write name and structural formula of one example each.


Give names of three functional groups containing three different hetero atoms. Write name and structural formula of one example each.


Find the odd one out and give its explanation.


Find the odd one out and give its explanation.


Find the odd one out and give its explanation.


Write the molecular formula of the given compound.

Propene


Cyclohexane is a branched chain type of hydrocarbon.


Explain the Catenation power.


Distinguish between:

Saturated hydrocarbons - Unsaturated hydrocarbons


Distinguish between:

Open chain hydrocarbons - Closed chain hydrocarbons


Write a short note.

Catenation power


Complete the given chart with writing the correct functional group of carbon compounds.

(Ester, Aldehyde, Ketone, Carboxylic acid, Alcohol, Ether)

  -O-H
  \[\begin{array}{cc}
\ce{O}\phantom{..}\\
||\phantom{..}\\
\ce{-C-H}
\end{array}\]
  \[\begin{array}{cc}
\ce{O}\\
||\\
\ce{-C-}
\end{array}\]
  \[\begin{array}{cc}
\ce{O}\phantom{.....}\\
||\phantom{.....}\\
\ce{-C-O-H}
\end{array}\]
  -O-
  \[\begin{array}{cc}
\ce{O}\phantom{..}\\
||\phantom{..}\\
\ce{-C-O}
\end{array}\]
 

\[\begin{array}{cc}
\ce{-N-H}\\
|\phantom{..}\\
\ce{H}\phantom{..}
\end{array}\]


Match the following.

Functional group –OH - Benzene
Heterocyclic - Potassium stearate
Unsaturated - Alcohol
Soap - Furan
Carbocyclic - Ethene

Which of these is true for most of the organic compounds?


Which of the following is not a straight chain hydrocarbon?


______ is the functional group of carboxylic acid.


Write the IUPAC name of the following:

\[\begin{array}{cc}
\ce{CH3}\phantom{...}\ce{CH3}\phantom{.......}\\
|\phantom{.......}|\phantom{.........}\\
\ce{CH2 - CH - CH2}\\
\phantom{...........}|\\
\phantom{......................}\ce{CH2}\ce{CH2}\ce{CH3}
\end{array}\]


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