Advertisements
Advertisements
प्रश्न
Factorise the following:
1 – 64a3 – 12a + 48a2
योग
उत्तर
1 – 64a3 – 12a + 48a2 = (1)3 – (4a)3 – 3 × 12 × 4a + 3 × 1 × (4a)2
= (1 – 4a)3 ...[Using identity, (a – b)3 = a3 – b3 – 3a2b + 3ab2]
= (1 – 4a)(1 – 4a)(1 – 4a)
shaalaa.com
Factorisation of Polynomials
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Polynomials - Exercise 2.3 [पृष्ठ २१]
APPEARS IN
संबंधित प्रश्न
Factorise:
12x2 – 7x + 1
Factorise:
x3 – 2x2 – x + 2
Determine the following polynomial has (x + 1) a factor:
`x^3-x^2-(2+sqrt2)x+sqrt2`
Factorize the following polynomial.
(x – 5)2 – (5x – 25) – 24
Factorize the following polynomial.
(x2 – 6x)2 – 8 (x2 – 6x + 8) – 64
Show that x + 3 is a factor of 69 + 11x – x2 + x3.
Factorise:
x2 + 9x + 18
Factorise:
6x2 + 7x – 3
Factorise:
`2sqrt(2)a^3 + 8b^3 - 27c^3 + 18sqrt(2)abc`
If both x – 2 and `x - 1/2` are factors of px2 + 5x + r, show that p = r.
