Advertisements
Advertisements
प्रश्न
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
उत्तर
9x5 + 6x3y2 – 18x2y = (3 × 3 × x2 × x3 × y × y) + (2 × 3 × x2 × x × y × y) – (2 × 3 × 3 × x2 × y)
Taking out the common factors 3, x2, y, we get
= 3 × x2 × y(3x3y2 + 2xy – 6)
= 3x2y(3x3y2 + 2xy – 6)
APPEARS IN
संबंधित प्रश्न
Factorise the following expression:
7x − 42
Factorise the following expression:
−16z + 20z3
Factorise the following expression:
20 l2m + 30 alm
Factorise the following expression:
10a2 − 15b2 + 20c2
Factorise.
15xy − 6x + 5y − 2
Factorize the following:
3x − 9
Factorize the following:
ax2y + bxy2 + cxyz
Factorise by taking out the common factors :
2 (2x - 5y) (3x + 4y) - 6 (2x - 5y) (x - y)
Factorise : `x^2 + [a^2 + 1]/a x + 1`
Factorise:
(2a - 3)2 - 2 (2a - 3) (a - 1) + (a - 1)2
Factorise : (a2 - a) (4a2 - 4a - 5) - 6
Find the value of : ( 987 )2 - (13)2
Factorise : 4a2 - 8ab
factorise : a2 - ab - 3a + 3b
factorise : m - 1 - (m-1)2 + am - a
Factorise: a4 - 625
Factorise the following by taking out the common factors:
81(p + q)2 -9p - 9q
Factorise:
4x4 + 25y4 + 19x2y2