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Factorise the following by taking out the common factor 9x5y3 + 6x3y2 – 18x2y - Mathematics

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प्रश्न

Factorise the following by taking out the common factor

9x5y3 + 6x3y2 – 18x2y

योग

उत्तर

9x5 + 6x3y2 – 18x2y = (3 × 3 × x2 × x3 × y × y) + (2 × 3 × x2 × x × y × y) – (2 × 3 × 3 × x2 × y)

Taking out the common factors 3, x2, y, we get

= 3 × x2 × y(3x3y2 + 2xy – 6)

= 3x2y(3x3y2 + 2xy – 6)

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अध्याय 3: Algebra - Exercise 3.4 [पृष्ठ ९६]

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सामाचीर कलवी Mathematics [English] Class 8 TN Board
अध्याय 3 Algebra
Exercise 3.4 | Q 1. (ii) | पृष्ठ ९६
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