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Find the Equation of the Line Passing Through ( 2 , 2 √ 3 ) and Inclined with X-axis at an Angle of 75°. - Mathematics

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प्रश्न

Find the equation of the line passing through \[(2, 2\sqrt{3})\] and inclined with x-axis at an angle of 75°.

संक्षेप में उत्तर

उत्तर

\[\text { Here, } m = \tan {75}^\circ \]

\[ \Rightarrow m = \tan\left( {45}^\circ + {30}^\circ \right)\]

\[ \Rightarrow m = \frac{\tan {45}^\circ + \tan {30}^\circ}{1 - \tan {45}^\circ \tan {30}^\circ}\]

\[ \Rightarrow m = \frac{1 + \frac{1}{\sqrt{3}}}{1 - \frac{1}{\sqrt{3}}} = \frac{\sqrt{3} + 1}{\sqrt{3} - 1}\]

\[ \Rightarrow m = \frac{\sqrt{3} + 1}{\sqrt{3} - 1} \times \frac{\sqrt{3} + 1}{\sqrt{3} + 1} = 2 + \sqrt{3}\]

So, the equation of the line that passes through \[(2, 2\sqrt{3})\] and has slope \[2 + \sqrt{3}\] is

\[y - 2\sqrt{3} = \left( 2 + \sqrt{3} \right)\left( x - 2 \right)\]

\[ \Rightarrow y - 2\sqrt{3} = \left( 2 + \sqrt{3} \right)x - 4 - 2\sqrt{3}\]

\[ \Rightarrow \left( 2 + \sqrt{3} \right)x - y - 4 = 0\]

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Straight Lines - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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अध्याय 23: The straight lines - Exercise 23.4 [पृष्ठ २९]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.4 | Q 4 | पृष्ठ २९

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